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375x-10x^2=37
We move all terms to the left:
375x-10x^2-(37)=0
a = -10; b = 375; c = -37;
Δ = b2-4ac
Δ = 3752-4·(-10)·(-37)
Δ = 139145
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(375)-\sqrt{139145}}{2*-10}=\frac{-375-\sqrt{139145}}{-20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(375)+\sqrt{139145}}{2*-10}=\frac{-375+\sqrt{139145}}{-20} $
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